SOLUTION: 3. A division has 12 employees, 8 males and 4 females.
(a) (3 points) In how many ways can a committee of 6 members can be selected from out of these 12?
12c6 = 924 ways
(b) (3
Algebra ->
Probability-and-statistics
-> SOLUTION: 3. A division has 12 employees, 8 males and 4 females.
(a) (3 points) In how many ways can a committee of 6 members can be selected from out of these 12?
12c6 = 924 ways
(b) (3
Log On
Question 601051: 3. A division has 12 employees, 8 males and 4 females.
(a) (3 points) In how many ways can a committee of 6 members can be selected from out of these 12?
12c6 = 924 ways
(b) (3 points) Find the probability that a random committee contains all males?
P(6 males) = 8C6/12C6 = 28/924
(c) (3 points) Suppose that the committee should have one President which has to be a female and two ordinary members who must be males.
How many different committees are possible?
4 x 8 x 7 x 9 x 8 x 7 = 112896
are any of these correct? Answer by jim_thompson5910(35256) (Show Source):
(