SOLUTION: What is the probability that a 5 card poker hand has 2 queens, given that all 5 cards are red cards?
My impression is this is an intersection problem { P(X and Y) = P(X) + P(Y)
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-> SOLUTION: What is the probability that a 5 card poker hand has 2 queens, given that all 5 cards are red cards?
My impression is this is an intersection problem { P(X and Y) = P(X) + P(Y)
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Question 588149: What is the probability that a 5 card poker hand has 2 queens, given that all 5 cards are red cards?
My impression is this is an intersection problem { P(X and Y) = P(X) + P(Y) - P(X)*P(Y) } ? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What is the probability that a 5 card poker hand has 2 queens, given that all 5 cards are red cards?
# of ways to succeed: 2C2*24C3 = 2024
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# of possible 5 red-card hands: 26C5 = 65780
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P(condition met) = 2024/65780 = 0.0308
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Cheers,
Stan H.
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