SOLUTION: Hi, There are 12 red beads and 12 green beads. Choose 4 beads randomly. 1. What are the chances that 4 out of 4 beads will be red? (12/24)^4 seems correct. But why would

Algebra ->  Probability-and-statistics -> SOLUTION: Hi, There are 12 red beads and 12 green beads. Choose 4 beads randomly. 1. What are the chances that 4 out of 4 beads will be red? (12/24)^4 seems correct. But why would      Log On


   



Question 576800: Hi,
There are 12 red beads and 12 green beads. Choose 4 beads randomly.
1. What are the chances that 4 out of 4 beads will be red?
(12/24)^4 seems correct. But why wouldn't 12C4/24C4 be correct? I'm having trouble understanding when to use which formula.
2. What are the chances that 3 out of 4 beads will be red?
12C3+12C4/24C4 <--- is this correct?

Thanks!

Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

1. 12C4 / 24C4
2. [ 12C3 * 12C1] /24C4

if any doubt, feel free to ask...