SOLUTION: The length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. Find
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Question 565281: The length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. Find the probability that a customer will wait between 4 and 8 minutes? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of time a customer must wait in line at the post office has approximately a normal distribution with a mean of 5.8 minutes and a standard deviation of 2.6 minutes. Find the probability that a customer will wait between 4 and 8 minutes?
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z(4) = (4-5.8)/2.6 = -0.6923
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z(8) = (8-5.8)/2.6 = 0.8462
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P(4 < x < 8) = P(-0.6923 < z < 0.8462) = 0.7556
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Cheers,
Stan H.
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