SOLUTION: A box contains 11 nickels, 4 dimes, and 5 quarters. If you draw 3 coins at random from the box without replacement, what is the probability that you will get a nickel, a dime, and
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-> SOLUTION: A box contains 11 nickels, 4 dimes, and 5 quarters. If you draw 3 coins at random from the box without replacement, what is the probability that you will get a nickel, a dime, and
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Question 549462: A box contains 11 nickels, 4 dimes, and 5 quarters. If you draw 3 coins at random from the box without replacement, what is the probability that you will get a nickel, a dime, and a nickel, in that order? Answer by TutorDelphia(193) (Show Source):
You can put this solution on YOUR website! The prob of getting a nickel is 11/20
Now one coin is removed but we still have 4 dimes so the prob of getting a dime is 4/19
and a nickel will be 10/18 since there is one nickel gone and two coins gone
We multiply these probabilities together and get which after some multiplication of fractions (top times top bottom times bottom) and simplifying we get 11/171
