SOLUTION: A new automobile comes with the choices of 5 colors & 3 different engine types. Then there is a list of 12 possible options to include in your new car. you can choose any number of

Algebra ->  Probability-and-statistics -> SOLUTION: A new automobile comes with the choices of 5 colors & 3 different engine types. Then there is a list of 12 possible options to include in your new car. you can choose any number of      Log On


   



Question 542974: A new automobile comes with the choices of 5 colors & 3 different engine types. Then there is a list of 12 possible options to include in your new car. you can choose any number of these options, from none to all 12. How many different possible automobiles must the factory be prepared to build.
I tried doing 5*3*12 but i wasnt sure if that was the correct way to solve the problem.. & then i attempted to use what is called nPr where i did 12! divided by 5!*3! but once again i wasnt quite sure if that was correct.. Help please?

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A new automobile comes with the choices of 5 colors & 3 different engine types. Then there is a list of 12 possible options to include in your new car. you can choose any number of these options, from none to all 12. How many different possible automobiles must the factory be prepared to build.
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Each of the options is either chosen or not chosen: there are 2^12 possibilities.
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Ans: 5*3*2^12 = 61,440 different configurations
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+5%2A3+ gives all the combinations
of color and engine type
Of the options, The 1st selection can be
none or any 1 of 12- that makes 13 choices
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that leaves 12 choices for the 2nd selection
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The result of this is +13%21+
+5%2A3%2A13%21+ answer
I'm pretty sure, but you may
want a 2nd opinion