SOLUTION: Consider a die with eight sides, marked one, two, three, and so on.
Assuming equally likely outcomes, find the probability that the sum of
two dice is the given number.
P(4)=
Algebra ->
Probability-and-statistics
-> SOLUTION: Consider a die with eight sides, marked one, two, three, and so on.
Assuming equally likely outcomes, find the probability that the sum of
two dice is the given number.
P(4)=
Log On
Question 536742: Consider a die with eight sides, marked one, two, three, and so on.
Assuming equally likely outcomes, find the probability that the sum of
two dice is the given number.
P(4)=
P(7)=
P(15)=
I'm thinking that the sum(4) of two die will be 1+3, and 2+2. So that's only two out comes for a 4. But how do yo find the # of possibilities? Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! for P(4) ___ 1+3, 2+2, 3+1 ___ 3 outcomes (same numbers on different dice is different outcome)
any of the 8 numbers on one die can be paired with any of the 8 numbers on the other die
___ 8 * 8 = 64 possibilities
