Question 526459: What is the probability that out of 23 numbers that exactly two people will choose an even number? The number chosen by each person does not have to be the same number,just one of the 11 even numbers. Out of the 23 numbers, 11 are even and 12 are odd.
11 even are 2,4,6,8,10,12,14,16,18,20 and 22.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What is the probability that out of 23 persons that exactly two people will choose an even number? The number chosen by each person does not have to be the same number,just one of the 11 even numbers. Out of the 23 numbers, 11 are even and 12 are odd.
11 even are 2,4,6,8,10,12,14,16,18,20 and 22.
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Binomial Problem with n = 23 and p(even) = 11/23
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P(x = 2) = 23C2(11/23)^2*(12/23)^21 = 0.000067448...
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Cheers,
Stan H.
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