SOLUTION: A binomial random variable has a mean equal to 181 and a standard deviation of 6.
Find the value of n.
Find the value of p
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-> SOLUTION: A binomial random variable has a mean equal to 181 and a standard deviation of 6.
Find the value of n.
Find the value of p
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Question 526401: A binomial random variable has a mean equal to 181 and a standard deviation of 6.
Find the value of n.
Find the value of p Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A binomial random variable has a mean equal to 181
and a standard deviation of 6.
Find the value of n.
Find the value of p
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mean = np = 181
std = sqrt(npq) = 6
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npq = 6^2 = 36
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npq/np = 36/181
q = 36/181
Then p = 1-(36/181) = 145/181
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Solve for "n":
np = 181
n = 181/(145/181) = 181^2/145 = 226 when rounded up
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Cheers,
Stan H.
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