SOLUTION: Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9. What is the proba

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Question 481093: Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9.
What is the probability that Person B hit the target given that both of them fired and exactly one shot hit the target?
a. 0.18
b. 0.30
c. 0.69
d. 0.90
I came up with .50*.80 =.40 and .50*.90=.45 thus .40*.45=0.18 Is this correct?
Thank you
Found 2 solutions by stanbon, robertb:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9.
What is the probability that Person B hit the target given that both of them fired and exactly one shot hit the target?
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The events are independent.
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P(B hit and A missed) = 0.9*0.2 = 0.18
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Cheers,
Stan H.
a. 0.18
b. 0.30
c. 0.69
d. 0.90

Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website!
If exactly one of them hits the target, then the probability is 0.80*0.10 + 0.90*0.20 = 0.26.
Hence the the probability that person B hit the target given that both of them fired is , or 0.69 to 2 decimal places.

c. 0.69