SOLUTION: A bus stop has 7 stops and 4 passengers. Given that a passenger is equally likely to get off at any stop, what is the probaility that 2 will get off at the same stop?
Algebra ->
Probability-and-statistics
-> SOLUTION: A bus stop has 7 stops and 4 passengers. Given that a passenger is equally likely to get off at any stop, what is the probaility that 2 will get off at the same stop?
Log On
Question 479302: A bus stop has 7 stops and 4 passengers. Given that a passenger is equally likely to get off at any stop, what is the probaility that 2 will get off at the same stop? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bus stop has 7 stops and 4 passengers. Given that a passenger is equally likely to get off at any stop, what is the probability that 2 will get off at the same stop?
---
Binomial Problem with n = 4 and p = 1/7
-----
P(x = 2) = 4C2*(1/7)^2(6/7)^2 = 0.09
=============
cheers,
Stan H.