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Hi,
For a normal distribution, find the value of z such that 36% of the total area is to the right of z
|Using Excel function NORMSINV(0.36)= -.3585
P(z = -.3585) represents the total area to the 'left' of z being 36%
P(z = .3585) represents the total area to the 'right' of z being 36%