SOLUTION: Another problem I need help with In a recent year, the mean number of strokes per hole for a famous golfer was approximately 3.8. Find the variance and standard deviation usin

Algebra ->  Probability-and-statistics -> SOLUTION: Another problem I need help with In a recent year, the mean number of strokes per hole for a famous golfer was approximately 3.8. Find the variance and standard deviation usin      Log On


   



Question 473886: Another problem I need help with
In a recent year, the mean number of strokes per hole for a famous golfer was approximately 3.8.
Find the variance and standard deviation using the fact that the variance of a Poisson distribution is σ2=μ.
How likely is this golfer to play an 18-hole round have more than 72 strokes?
The variance is= (round to the nearest tenth as needed)
The Standard deviation is_________ Strokes. (round to the nearest then as needed.)
The probability of more than 72 strokes in an 18-hole is____(round to the nearest thousandth as needed)
Thank you.

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
mu+=+sigma%5E2+=+3.8%2A18+=+68.4
==> sigma+=+sqrt%2868.4%29+=+8.3
==> The probability of more than 72 strokes in an 18-hole = 1-e%5E%28-68.4%29%2Asum%2868.4%5Ex%2Fx%21%2C+x+=+0%2C+72%29.