Question 455854: . An average computer mouse inspector can inspect 40 mice per hour with a population standard deviation of 8 mice per hour. The 50 computer mice inspectors at a particular factory can only inspect 34 mice per hour. Does the company have reason to believe that these inspectors are slower than average at α = 0.10?
A) Yes, because the test value –5.30 falls in the noncritical region.
B) No, because the test value –3.03 falls in the critical region.
C) Yes, because the test value –5.30 falls in the critical region.
D) No, because the test value –3.03 falls in the noncritical region.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An average computer mouse inspector can inspect 40 mice per hour with a population standard deviation of 8 mice per hour. The 50 computer mice inspectors at a particular factory can only inspect 34 mice per hour. Does the company have reason to believe that these inspectors are slower than average at α = 0.10?
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Ho: u50 - uave >= 0
Ha: u(50)-uave < 0 (claim)
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test stat: t(34) = (34-40)/[8/sqrt(49)] = -5.25
p-value = P(t < -5.25 when df = 49) = tcdf(-100,-5.25,49) = 0.0000016323..
Reject Ho.
Test values support the claim these inspectors are slower than average.
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Critical value = invT(0.10 when df = 49) = -1.2991
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Ans: C
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Cheers,
Stan H.
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A) Yes, because the test value –5.30 falls in the noncritical region.
B) No, because the test value –3.03 falls in the critical region.
C) Yes, because the test value –5.30 falls in the critical region.
D) No, because the test value –3.03 falls in the noncritical region.
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