Question 440006: On a History test, where the student grades are distributed normally, the average grade was 78 and the standard deviation was 10. Determine the numeric score of two students whose standard scores (a.k.a. z-scores) were -0.6 and 1.2, respectively.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! On a History test, where the student grades are distributed normally, the average grade was 78 and the standard deviation was 10. Determine the numeric score of two students whose standard scores (a.k.a. z-scores) were -0.6 and 1.2, respectively.
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Since z = (x-u)/s, x = zs + u
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Your Problem:
x(-0.6) = -0.6*10+78 = 72
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x(1.2) = 1.2*10 + 78 = 90
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Cheers,
Stan H.
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