Question 437571: Dawn, Serigo, Katrina, Sarah, Ian, Maria, and Kim have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) In how many ways can they arrive?
b) In how many ways can Dawn arrive first and Kim last?
c)Find the probability that Dawn will arrive first and Kim last.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Dawn, Serigo, Katrina, Sarah, Ian, Maria, and Kim have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) In how many ways can they arrive?:: 7!
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b) In how many ways can Dawn arrive first and Kim last?::1*5!*1 = 5!
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c)Find the probability that Dawn will arrive first and Kim last.
Ans 5!/7! = 1/(7*6) = 1/42
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cheers,
Stan H.
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