SOLUTION: A bag contains 10 green candies, 3 red candies, and 5 orange candies. What is the probability of drawing and eating first a green, then a red, and then an orange candy?

Algebra ->  Probability-and-statistics -> SOLUTION: A bag contains 10 green candies, 3 red candies, and 5 orange candies. What is the probability of drawing and eating first a green, then a red, and then an orange candy?       Log On


   

Question 426696: A bag contains 10 green candies, 3 red candies, and 5 orange
candies.
What is the probability of drawing and eating first a green, then a
red, and then an orange candy?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

 18 candies in all: 10 green, 3 red and 5 orange

Drawing with no replacement :)

P(green, red, orange) =  10/18*3/17*5/16