SOLUTION: solve this :
2sin3x=1
when 0 < or equal to x < or equal to 90
Algebra.Com
Question 425456: solve this :
2sin3x=1
when 0 < or equal to x < or equal to 90
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Solution: 2sin3x=1 => sin3x=1/2 => 3x=30(degree) =>x=10(degree)
Since the sinx is periodic function with period we have:
for 0< x <90
The solution in radian will be:
and the solution will be:
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