SOLUTION: Hi,
I'm trying to solve a problem around coin flips. If the probability of a "win" is .48 and I'm not going to stop flipping until I've reached 10 wins or 10 losses, what are
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-> SOLUTION: Hi,
I'm trying to solve a problem around coin flips. If the probability of a "win" is .48 and I'm not going to stop flipping until I've reached 10 wins or 10 losses, what are
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Question 402725: Hi,
I'm trying to solve a problem around coin flips. If the probability of a "win" is .48 and I'm not going to stop flipping until I've reached 10 wins or 10 losses, what are the odds of reaching each number?
Thanks in advance!!!
Dmitry Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I'm trying to solve a problem around coin flips. If the probability of a "win" is .48 and I'm not going to stop flipping until I've reached 10 wins or 10 losses, what are the odds of reaching each number?
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odds for a win = [P(win)/P(not win)] = 0.48/0.52 = 12:13
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Cheers,
Stan H.
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