Question 394742: A computer program is tested by 3 independent tests. When there is an error, these
tests will discover it with probabilities 0.2, 0.3, and 0.5, respectively. Suppose that the program
contains an error. What is the probability that it will be found by at least one test?
Answer by jrfrunner(365)   (Show Source):
You can put this solution on YOUR website! let A =error found by test 1
let B=error found by test 2
let C=error found by test 3
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Given P(A)=0.2, P(B)=0.3, P(C)=0.5
therefore P(notA)=0.8, P(notB)=0.7, P(notC)=0.5
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Note: tests are independent P(notA & notB & notC)=P(notA)*P(notB)*P(notC)=0.8*0.7*0.5=0.28
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P(found by at least one test)= 1- P(not found by any test)=1-P(notA & notB & notC)=1-0.28=0.82
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