SOLUTION: 5.Three computer viruses arrive as an email attachment. Virus A damages the system with probability 0.4. Independently of it, virus B damages the system with probability 0.5. Indep
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Question 394621: 5.Three computer viruses arrive as an email attachment. Virus A damages the system with probability 0.4. Independently of it, virus B damages the system with probability 0.5. Independently of A and B, virus C damages the system with probability 0.2. What is the probability that the system gets damaged? Answer by jrfrunner(365) (Show Source):
You can put this solution on YOUR website! if the viruses are truly independent then
probability that the system gets damaged=
P(AUBUC)=P(A)+P(B)+P(C)-P(AnB)-P(anc)-P(bnc)+P(AnBnC)=
0.4+0.5+0.2-0.4*0.5-0.4*0.2-0.5*0.2+0.4*0.5*0.2=1.1-0.2-0.08-0.1+0.04
=0.76
