SOLUTION: A pair of 8 sided dice have sides numbered 1 through 8. Each side has the same probability of landing face up. Find the probability that the product of the 2 numbers on the sides

Question 39272: A pair of 8 sided dice have sides numbered 1 through 8. Each side has the same probability of landing face up. Find the probability that the product of the 2 numbers on the sides that land face up exceeds 36.
Found 2 solutions by Nate, josmiceli:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Number of Ways to Get More than 36:
5:8
6:7
6:8
7:6
7:7
7:8
8:5
8:6
8:7
8:8
There are eight different ways to achieve this:
10/(8*8)
(5/32)
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I get 10/64 or 5/32 for an answer.
The combinations of die numbers that ass up to greater than 36 are:
die 1: 7
die 2: 6 or 7 or 8
-----------------------
die 1: 8
die 2: 5 or 6 or 7 or 8
------------------------
die 1: 6
die 2: 7 or 8
-----------------------
die 1: 5
die 2: 8
-----------------------
That covers all the possibilities
Now add them up. Whenever you want the probability, P of a OR b,
P = a + b.
There are 10 ways to get side 1 + side 2 greater than 36
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