SOLUTION: Which pair has equally likely outcomes? Check the two choices below which have equal probabilities of success. A standard deck of cards has 12 face cards and four Aces (Aces are no

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Question 387566: Which pair has equally likely outcomes? Check the two choices below which have equal probabilities of success. A standard deck of cards has 12 face cards and four Aces (Aces are not face cards).

rolling a sum of 4 on two fair six sided dice
drawing a black seven out of a standard 52 card deck given it’s not a face card or an Ace.
rolling a sum of 11 on two fair six sided dice
rolling a sum of 7 on two fair six sided dice
drawing a three out of a standard 52 card deck given it’s not a face card or an Ace

the fractions I come up with no matches
1/13 drawing 3 out of deck of cards
2/52 drawing a black 7 out of deck of cards
6/36 = 1/6 rolling 7
2/36 rolling 11
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
rolling a sum of 4 on two fair six sided dice:::3/36 = 1/12
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drawing a black seven out of a standard 52 card deck given it’s not a face card or an Ace. ::: 2/36 = 1/18
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rolling a sum of 11 on two fair six sided dice:::2/36 = 1/18
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rolling a sum of 7 on two fair six sided dice:::1/6
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drawing a three out of a standard 52 card deck
given it’s not a face card or an Ace:::4/36 = 1/9
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Cheers,
Stan H.
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1/13 drawing 3 out of deck of cards
2/52 drawing a black 7 out of deck of cards
6/36 = 1/6 rolling 7
2/36 rolling 11
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Must take into account the given when considering the card questions.

Otherwise You are on the right track!!

GIVEN it's not a face card or an ace...      

drawing a black seven out of a standard 52 card deck 

52 - 4aces - 12face cards = 36 possibilities P = 2/36 = 1/18 *

drawing a 3 out of a standard 52 card deck  4/36 = 1/9



 rolling a sum of 4 on two fair six sided dice. P = 3/36 = 1/12 

 rolling a sum of 11 on two fair six sided dice. P = 2/36 = 1/18 *

 rolling a sum of 7 on two fair six sided dice.  P = 6/36 = 1/6

those starred have equal probabilities of success

___1_2_3__4__5__6

1|_2_3_4__5__6__7

2|_3_4_5__6__7__8

3|_4_5_6__7__8__9

4|_5_6_7__8__9_10

5|_6_7_8__9_10_11

6|_7_8_9_10_11_12