SOLUTION: Find the probability of getting at least three defective items in a batch of ten items if the overall percentage of defects is 40%

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Question 357696: Find the probability of getting at least three defective items in a batch of ten items if the overall percentage of defects is 40%
Answer by Fombitz(32388) About Me  (Show Source):
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Find the probability for 0 to 10 defective items.
P%280%29=1%2A%280.6%29%5E%2810-0%29%2A%280.4%29%5E%280%29=0.00605
P%281%29=10%2A%280.6%29%5E%2810-1%29%2A%280.4%29%5E%281%29=0.04031
P%282%29=45%2A%280.6%29%5E%2810-2%29%2A%280.4%29%5E%282%29=0.12093
P%283%29=120%2A%280.6%29%5E%2810-3%29%2A%280.4%29%5E%283%29=0.21499
P%284%29=210%2A%280.6%29%5E%2810-4%29%2A%280.4%29%5E%284%29=0.25082
P%285%29=252%2A%280.6%29%5E%2810-5%29%2A%280.4%29%5E%285%29=0.20066
P%286%29=210%2A%280.6%29%5E%2810-6%29%2A%280.4%29%5E%286%29=0.11148
P%287%29=120%2A%280.6%29%5E%2810-7%29%2A%280.4%29%5E%287%29=0.04247
P%288%29=45%2A%280.6%29%5E%2810-8%29%2A%280.4%29%5E%288%29=0.01062
P%289%29=10%2A%280.6%29%5E%2810-9%29%2A%280.4%29%5E%289%29=0.00157
P%2810%29=1%2A%280.6%29%5E%2810-10%29%2A%280.4%29%5E%2810%29=0.00010
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P(at least 3)=
P(at least 3)= 1-0.00605-0.04031-0.12093
P(at least 3)= highlight%280.83271%29