SOLUTION: a girl has 10 yellow, 10 red, and 10 green marbles. She picks two marbles out at random and gives them to her sister
a.) what is the probability of choosing 2 yellow marbles?
b
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-> SOLUTION: a girl has 10 yellow, 10 red, and 10 green marbles. She picks two marbles out at random and gives them to her sister
a.) what is the probability of choosing 2 yellow marbles?
b
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Question 352933: a girl has 10 yellow, 10 red, and 10 green marbles. She picks two marbles out at random and gives them to her sister
a.) what is the probability of choosing 2 yellow marbles?
b.) of the marbles left what is the probability of choosing a green marble next?
c.)of the marbles left, what color has the probability of 1/3 of being picked? explain how you determined your answer. Found 2 solutions by stanbon, robertb:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a girl has 10 yellow, 10 red, and 10 green marbles. She picks two marbles out at random and gives them to her sister
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a.) what is the probability of choosing 2 yellow marbles?
P(2 yellow) = 10C2/30C2 = 0.1034
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b.) of the marbles left what is the probability of choosing a green marble next?
P(green after 2 yellow) = 10/28
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c.)of the marbles left, what color has the probability of 1/3 of being picked? explain how you determined your answer.
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27 marbles are left
There are 9 green left.
P(green) = 9/27 = 1/3
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Cheers,
Stan H.
You can put this solution on YOUR website! The number of ways of getting 2 marbles out of 30 is C(30, 2).
The number of ways of getting 2 yellow marbles out of 10 yellow marbles is
C(10, 2).
a.) Thus The probability of choosing 2 yellow marbles is
b.) Of the marbles left there are 8 yellow, 10 red , 10 green. Thus the probability of choosing 1 green marble next is .
c.) After picking a green marble, there are 8 yellow, 10 red, 9 green marbles left. So there are 27 marbles remaining. Of these the green colored marble has probability of being picked.
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