Question 346756: From a group of 5 women and 7 men, how many different committees consisting of 2 women and 3 men can be formed? What if 2 men are feuding and refuse to serve on the committee together?
Answer by jrfrunner(365)   (Show Source):
You can put this solution on YOUR website! C(5,2) ways to choose the women
C(7,3) ways to choose the men
so C(5,2)*C(7,3)=10*35=350
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if two men are fighting and do not want to be in the same committe
C(6,3) basically is like there only 6 men available
so C(5,2)*C(6,3)=10*20=200
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