SOLUTION: How many different arrangements can be formed using the letters P E P P E R

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Question 346751: How many different arrangements can be formed using the letters P E P P E R
Found 2 solutions by nyc_function, Edwin McCravy:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
6P6 = 6! = 720 = our numerator.

The denominator will be 2!(3!).

Let 2! = the repeated letter E

Let 3! = the repeated letter P

6P6 = 720/2!(3!)

6P6 = 720/(2 x 6)

6P6 = 720/12

6P6 = 60





Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

P E P P E R

If we could tell the difference between the P's, and also tell
the difference between the E's, like this:

P E P P E R 

then the number of arrangements would be 6! or 720.  

However since the P's are indistinguishable,
each permutation of the 720, is counted too many times
as many as the number of ways the three P's can be arranged
in each permutation times the number of ways that the 2 E's can
be arranged in each permutation.  Therefore we divide by 3!*2!

Answer 

Edwin