Question 346312: Scoring a hole-in-one is the greatest shot a golfer can make. Once 8 professional golfers each made holes-in-one on the 7th hole at the same golf course at the same tournament. It has been found that the estimated probability of making a hole-in-one is 1/2722 for male professionals. Suppose that a sample of 8 professional male golfers is randomly selected.
What is the probability that at least one of these golfers makes a hole-in-one on the 13th hole at the same tournament?
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! "at least one" is the complementary event for "none"
So, we calculate the probability that none of them score a hole-in-one. Then we
subtract this probability from 1, because if it isn't true that no-one does,
then at least one of them does.
For each golfer, prob of not scoring hole-in-one
= 1 - 1/2722
= 2721/2722
Hence prob that all 8 fail to do so
= (2721/2722)^8
= 0.997 correct to 3 decimal places.
Therefore, the probability that at least one does
= 1 - 0.997
= 0.003
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