SOLUTION: : There is 7 friends (A1,A2,A3....A7).If A1 have to have shake with all with out repeat. How many hand shakes possible?(I dont know the exact question but like this only)

SOLUTION: : There is 7 friends (A1,A2,A3....A7).If A1 have to have shake with all with out repeat. How many hand shakes possible?(I dont know the exact question but like this only)

Algebra.Com

Question 338808: : There is 7 friends (A1,A2,A3....A7).If A1 have to have shake with all with out repeat. How many hand shakes possible?(I dont know the exact question but like this only)

Answer by galactus(183) (Show Source): You can put this solution on YOUR website!
A1 can shake hands with 6 people, A2-A7
A2 can shake hands with 5 people, A3-A7
and so on
If there are n people, there are (n-1)! ways for them to shake hands.
In this case, 6!=720 ways.
RELATED QUESTIONS
This is a problem in the text book "Matrix Analysis and Applied Linear Algerbra" by Carl (answered by khwang)

i have invited nine people to a party. They all shake hands with me, and each pair shake... (answered by ikleyn)

if a1,a2,a3.... are in A.P Such tgat a2/a7=3/2, then the 13th term of A.P is (answered by ikleyn,MathTherapy)

Sum of the first 6 terms of a geometric progression equals to 63. Sum of the even terms (answered by Boreal)

If sum of a1+a2+a3+a4+a5+a6+a7+a8+a9+a10+a11+a12=360, find the sum of... (answered by palanisamy)

For an arithmetic progression, a1, a2, a3,..... aN, if a4/a7=2/3, find a6/a8. (answered by greenestamps)

Let A be the set of four-digit numbers A1,A2,A3,A4 where A1>A2>A3>A4,Then how many of A... (answered by math_helper,greenestamps)

How do I show proof for this problem? If u∈V, then 1u=u I have the following:... (answered by rothauserc)

a1=15, a2=3,... (answered by Fombitz)