SOLUTION: A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?

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Question 334468: A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?
Found 2 solutions by Fombitz, jrfrunner:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
6 Y-yellow
5 O-orange
11 total,
.
.
.
P(1 Y)=6%2F11
P(2 Y)=5%2F10=1%2F2
P(both Y)=%286%2F11%29%281%2F2%29=3%2F11

Answer by jrfrunner(365) About Me  (Show Source):
You can put this solution on YOUR website!
A doll toy chest contains 6 yellow dolls and five orange dolls. What is the probability of getting at random and without replacement, 2 yellow dolls?
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Total dolls = 11
let Y= yellow dolls
let O=orange dolls
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probability of getting at random and without replacement, 2 yellow dolls
P(YY)=P(Y on first choosing)*P(Y on second choosing / First choosing is Y)
P(YY)= (6/11)*(5/10)=(6/11)*(1/2)=3/11
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you first have 6 yellow dolls to choose from 11 dolls, after you make that selection, your total is reduced by 1 to 10 and if that was yellow, the yellows are reduced by 1 to 5 (since its without replacement)