Question 323536: Approximately 53% of all the US population have at least some college education. Choose 10 people at random. Find the probabilities.
A.Exactly 1/2 have some college education
B.At least 1 has some college education
C.Fewer than 5 have some college education
D. What is the most likely number of people that have some college education?
For parts A and B I used the factorial equation: P(x)= n!/x!(n-x)! *p^x(1-p)^n-x
For A I got: .242
For B I got: .006
Am I using the right equation to solve this problem?? I am really confused when it comes to part C and D. If you can let me know if I am using the right equation, and if my answers are correct, that would be great. Can you show me how to solve Part C and D? Thanks!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Approximately 53% of all the US population have at least some college education. Choose 10 people at random. Find the probabilities.
---
Binomial problem with n=10 ; p = 0.53
---
A.Exactly 1/2 have some college education
P(x=5) = 10C5*(0.53)^5(0.47)^5 = 0.2417
----------------------------------------------
B.At least 1 has some college education
P(x>=1) = 1 - P(x = 0)
= 1 - 10C0(0.53)^0*0.47^10
= 1 - 0.47^10
= 0.9997
====================================================
C.Fewer than 5 have some college education
I used a TI-84 to get:
P(0<= x <=4) = binomcdf(10,0,53,4) = 0.3057
-----------------------------------------------------
D. What is the most likely number of people that have some college education?
mean = E(x) = np = 10*0.53 = 5.3 people
==========================================
Cheers,
Stan H.
For parts A and B I used the factorial equation: P(x)= n!/x!(n-x)! *p^x(1-p)^n-x
For A I got: .242
For B I got: .006
|
|
|
