SOLUTION: Eighteen guests have to be seated,half on each side of a long table.If four particular guests desire to sit on one
particular side and three others on the other side,the number o
Algebra ->
Probability-and-statistics
-> SOLUTION: Eighteen guests have to be seated,half on each side of a long table.If four particular guests desire to sit on one
particular side and three others on the other side,the number o
Log On
Question 31493: Eighteen guests have to be seated,half on each side of a long table.If four particular guests desire to sit on one
particular side and three others on the other side,the number of ways in which the sitting arrangement can be made is
A.11C5*9!*9!
B.11C6*8!*10!
C.11C5*8!*10!
D.None of the above Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! 9 ARE TO BE ON 1 SIDE.4 ARE ALREADY ON ONE SIDE AND 3 ON OTHER SIDE.
THERE ARE 11 LEFT.
WE CAN SELECT 5 OF THEM IN 11C5 WAYS TO SIT ALONG WITH 4.
REST WILL AUTOMATICALLY GO TO OTHER SIDE.THIS CAN BE DONE IN ONLY 1 WAY .
NOW 9 ON EITHER SIDE CAN BE ARRANGED IN 9! WAYS...SO THE TOTAL NUMBER OF ARRANGEMENTS ARE
11C5*9!*9!.....A IS THE ANSWER
