SOLUTION: based on the information below decide whether to reject the null hypothesis. For each give the z-score cutoff on the comparison distribution at which the null hypothesis should be

Algebra ->  Probability-and-statistics -> SOLUTION: based on the information below decide whether to reject the null hypothesis. For each give the z-score cutoff on the comparison distribution at which the null hypothesis should be       Log On


   



Question 313768: based on the information below decide whether to reject the null hypothesis. For each give the z-score cutoff on the comparison distribution at which the null hypothesis should be rejected and give the Z-score on the comparison distribution for the sample score and the conclusion: There are four studies A-D each have a mean of 5 and an SD of 1, all have a sample score of 7. A & B have a p=.05 using a 1tailed test(high predicted) and 2 tailed test. C & D have a p=.01 using a 1tailed test(high predicted) and 2 tailed test.
If my math is right the cut off score is -2 ??

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
based on the information below decide whether to reject the null hypothesis.
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For each give the z-score cutoff on the comparison distribution at which the null hypothesis should be rejected and give the Z-score on the comparison distribution for the sample score and the conclusion:
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There are four studies A-D each have a mean of 5 and an SD of 1, all have a sample score of 7.
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A & B have a p=.05 using a 1 tailed test(high predicted) and 2 tailed test.
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C & D have a p=.01 using a 1 tailed test(high predicted) and 2 tailed test.
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If my math is right the cut off score is -2 ?
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I can't tell where this problem is going.
You say you have both and right tail and a 2-tail test and p=0.05 for both!
I assume you p-value is the probability of test results being more extreme
than what your test revealed. But that p-value cannot be the same for a
right tail and a 2 tail test.
What am I missing?
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Also, on a right tail test, a cut-off of z=-2 does not make much sense.
How did you arrive at that?
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Cheers,
Stan H.