SOLUTION: Given a normally distributed population with a mean of 30 and a standard deviation of 8 what percentage of the population will be found above 26?
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Question 297732: Given a normally distributed population with a mean of 30 and a standard deviation of 8 what percentage of the population will be found above 26? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Given a normally distributed population with a mean of 30 and a standard deviation of 8 what percentage of the population will be found above 26?
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Find the z-value of 26.
z(26) = (26-30)/8 = -0.5
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Then P(x > 26) = P(z > -0.5) = normalcdf(-0.5,100) = 0.6915
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Cheers,
Stan H.