SOLUTION: Hi, I need help with this problem, In a survay of 4722 American youngsters aged 6 to 19, 15 % were seriousy overweight (a body mass index of at least 30; this index is a measure

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Question 297157: Hi, I need help with this problem,
In a survay of 4722 American youngsters aged 6 to 19, 15 % were seriousy overweight (a body mass index of at least 30; this index is a measure of weight relative to height). calculate and interpret a confidence interval using a 99% confidence level for the porportion of all
American youngster who are seriously overweight.
Thank you
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a survey of 4722 American youngsters aged 6 to 19, 15 % were seriousy overweight (a body mass index of at least 30; this index is a measure of weight relative to height). calculate and interpret a confidence interval using a 99% confidence level for the porportion of all American youngster who are seriously overweight.
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sample proportion = 0.15
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standard error = 2.5758*sqrt(0.15*0.85/4722) = 0.01338
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99% CI: 0.15-0.01338 < p < 0.15+0.01338
99% CI: 0.1366 < p < 0.16338
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Cheers,
Stan H.