SOLUTION: a box contains a penny, a nickel, a dime, and a quarter. A coin is drawn at random and not replaced. a second coin is drawn. How many out comes are possible? thank you!

Algebra ->  Probability-and-statistics -> SOLUTION: a box contains a penny, a nickel, a dime, and a quarter. A coin is drawn at random and not replaced. a second coin is drawn. How many out comes are possible? thank you!      Log On


   



Question 293450: a box contains a penny, a nickel, a dime, and a quarter. A coin is drawn at random and not replaced. a second coin is drawn. How many out comes are possible?
thank you!

Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
first draw has 4 possible outcomes
second draw has 3 possible outcomes
4*3=12
If you consider that a penny drawn first and a nickel drawn second is the same as a nickel drawn first and a penny drawn second then we have only 6 outcomes.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st draw is 1 of 4.
The 2nd draw is 1 of 3.
3*4 = 12
But, a nickel and a dime is the same as a dime and a nickel, so divide by 2.
--> 6
------------
P N
P D
P Q
----
N D
N Q
---
D Q