Question 290629: I was trying to figure out a probability problem. Of 20 units in one lot. Each 20 unit lot has 10% defective items. what's the probability that the lot will be rejected? Accepted? Five or more items will in one lot is cause for rejection. I said it means there are at least 2 items in each 20 unit lot that is defective, which means the lot won't be rejected. I said it would be 0.05% chance it will be rejected and 0.95% chance it will be accepted.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I was trying to figure out a probability problem. Of 20 units in one lot. Each 20 unit lot has 10% defective items. what's the probability that the lot will be rejected? Accepted? Five or more items will in one lot is cause for rejection.
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Binomial Problem:
n = 20 ; 0.10
P(5<= x <=10) = 1 - P(0<= x <=4) = 1-binomcdf(20,0.1,4) = 0.04317...
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Cheers,
Stan H.
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