SOLUTION: Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed well. Two are drawn. What are the odds in favor of the sum of the numbers on the
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Question 289407: Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed well. Two are drawn. What are the odds in favor of the sum of the numbers on the two selected slips is not 6? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! 51 and 42 are the only combinations of 2 numbers whose sum is 6
nCr=7C2=21
2/21=probability that the sum of the numbers will be 6.
19 to 2 Odds in favor of the sum of the numbers on the two selected slips is not 6
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Ed
