SOLUTION: sam has a bag with 2 red, 7 yellow, and 5 blue marbles in it. if he pulls out 3 marbles, what is the probability that at least one of them is blue? 5/14 x 5/13 x 5/12 = 125/2184

Algebra ->  Probability-and-statistics -> SOLUTION: sam has a bag with 2 red, 7 yellow, and 5 blue marbles in it. if he pulls out 3 marbles, what is the probability that at least one of them is blue? 5/14 x 5/13 x 5/12 = 125/2184      Log On


   

Question 274686: sam has a bag with 2 red, 7 yellow, and 5 blue marbles in it. if he pulls out 3 marbles, what is the probability that at least one of them is blue?
5/14 x 5/13 x 5/12 = 125/2184
Found 2 solutions by stanbon, scott8148:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sam has a bag with 2 red, 7 yellow, and 5 blue marbles in it. if he pulls out 3 marbles, what is the probability that at least one of them is blue?
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P(at least one is blue) = 1 - P(none of the 3 is blue)
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= 1 - 9C3/14C3
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= 1 - 84/364
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= 1 - 0.2308
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= 0.7692
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Cheers,
Stan H.







5/14 x 5/13 x 5/12 = 125/2184

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
number of ways to draw 3 marbles ___ 14C3 = 364

number of ways to draw 3 marbles, with no blue ___ 9C3 = 84

so 280 draws (364 - 84) have at least one blue

probability of at least one blue ___ 280 / 364 = .77 (approx)