Question 269429: A bag of marbles contains 7 red, 3 blue, 5 white, 3 green.
A. P(red, red, white) with replacement
B.P(red, red, white) without replacement
Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A bag of marbles contains 7 red, 3 blue, 5 white, 3 green.
A. P(red, red, white) with replacement = (7/18)(7/18)(5/18) = 245/5832
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B.P(red, red, white) without replacement = (7/18)(6/17)(5/16) = 210/4896
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Cheers,
Stan H.
Answer by edjones(8007)  (Show Source):
You can put this solution on YOUR website! There are 18 marbles.
A) 7/18 * 7/18 * 5/18 = .042
.
B)
Combination=nCr=combination of n things taken r at a time.
(7C2 * 5C1)/3C18
=(21*5)/816
=105/816
=.1287
.
Ed
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