SOLUTION: There are 9 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittees are possible?

Algebra ->  Probability-and-statistics -> SOLUTION: There are 9 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittees are possible?      Log On


   



Question 260721: There are 9 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittees are possible?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
5 chosen from 9 gives the number of combinations as,
N=9%21%2F%285%21%289-5%21%29%29=9%2A8%2A7%2A6%2F%284%2A3%2A2%29=126