SOLUTION: When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement

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Question 228239: When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement
Found 2 solutions by drj, Edwin McCravy:
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement

Step 1. We note that there are 4 aces in a 52-card deck.

Step 2. The probability of an ace in the first card is P%28A%29=4%2F52=1%2F13 we call this the P(A)

Step 3. Since there is no replacement, there are only 3 aces out of the 51 cards since we assume an ace is drawn in the first card. Therefore, the probability of an ace on the second draw is P(B|A)=3%2F51. We call this P(B|A) where the Probability of drawing an Ace on the second draw given that Probability of A occurred or an ace was drawn on the first try. This is also known as a conditional probability.

Step 4. The probability is the product of the probabilities found in Steps 2 and 3. P(A and B)=P(B|A)P(A) or P(A and B)=3%2F51%2A1%2F13=3%2F663

Step 5. ANSWER: The probability of getting an ace followed by an ace without replacement is 3%2F663

I hope the above steps were helpful.

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Good luck in your studies!

Respectfully,
Dr J









Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
When a card is selected from a standard deck of cards, find the probability of getting an ace followed by an ace without replacement


P[getting an ace out of 52-card deck with 4 aces]

times

P[getting an ace out of a 51-card deck with 3 aces]

=

4%2F52x3%2F51 = 1%2F13x1%2F17=1%2F221

Edwin