SOLUTION: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face val

Algebra ->  Probability-and-statistics -> SOLUTION: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face val      Log On


   

Question 220593: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event : The sum is greater than 7.
Event : The sum is not divisible by 3.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
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Process: Sketch a 6 by 6 square with 1-6 naming the columns
and 1-6 naming the rows
Let the 36 entries be the sum of the row and column names.
You should end up with sums from 2 up to 12
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Compute the probability of each of the following events:
Event : The sum is greater than 7.
Find the count of these and divide by 36
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Event : The sum is not divisible by 3.
Find the count of these and divide by 36
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Cheers,
Stan H.