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Question 20300:

Found 2 solutions by suresh, JWG:
Answer by suresh(20) About Me  (Show Source):
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Sample space,S={10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30}
n(S)= 21.
Let A be the event of taking multiple of 4.
A = {12,16,20,24,28}
n(A) = 5.
Probability of A = number of favourable chance / Total chance.
P(A)= n(A)/ n(S).
= 5 / 21.
The probability of selecting multiple of 4 is 5/21.

Answer by JWG(21) About Me  (Show Source):
You can put this solution on YOUR website!
Number of Integers: 30-10+1=21
Multiples of Four between 10 and 30, inclusive: 12,16,20,24,28 (Five multiples of four)
Answer: 5/21