Question 198457: Please help! I haven't the foggiest idea how to do an example problem with this formula. I look at it and freeze. Can someone help me? (This is a homework assn.)
If there are “k” possible outcomes for a phenomenon and each is equally likely, then each individual outcome has a probability 1/k. The probability of any event A is:
P(A) = count of Outcomes in A / count of outcomes in S
= count of outcomes in / k
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Please help! I haven't the foggiest idea how to do an example problem with this formula. I look at it and freeze. Can someone help me? (This is a homework assn.)
If there are “k” possible outcomes for a phenomenon and each is equally likely, then each individual outcome has a probability 1/k. The probability of any event A is:
P(A) = count of Outcomes in A / count of outcomes in S
= count of outcomes in / k
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They are trying to defind the probability of an event.
Say you flip a coin.
# of heads is one
# of tails is one
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The are two possible outcomes.
P(head) = 1/2
P(tail) = 1/2
In this case k = 2
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Say you have a die with faces 1,2,3,4,5,6
Here k = 6
There is only one way to get each of the results.
P(1) = 1/6
P(2) = 1/6
P(3) = 1/6
etc.
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Say you have a family of three children.
The pattern could be bbb,bgg,gbg,ggb,bbg,bgb,gbb,ggg
So there are 8 possible results.
The probability of having 2 girls in a family of
three is 3/8
Here k = 8
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P(success) = [# of ways to succeed]/[# of possible outcomes]
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Hope this helps.
Cheers,
Stan H.
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