You can put this solution on YOUR website! Let a be the probability you will roll a 1 or 6 on 1 roll (1/3).
Let b be the probability you don't (2/3).
(2/3)^60=2.72*10^(-11) Probability all 60 rolls will not contain a 1 or 6.
1-2.720*10^(-11)
=.9999999999728
.
Ed