SOLUTION: 4) A number between 1 to 10 is selected at random twice. What is the probability that tha number selected in the second attempt is greater than the number selected previously.?
Algebra ->
Probability-and-statistics
-> SOLUTION: 4) A number between 1 to 10 is selected at random twice. What is the probability that tha number selected in the second attempt is greater than the number selected previously.?
Log On
Question 192708: 4) A number between 1 to 10 is selected at random twice. What is the probability that tha number selected in the second attempt is greater than the number selected previously.? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! This may or may not be of some help.
-----
The "average" number selectd on the 1st draw is 5.5.
--
Then the probability the 2nd draw will be greater is (5/10) = 1/2
-------------
Cheers,
Stan H.
(