Question 183329: Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86. (a) Construct a 90% confidence intervel for the proportion of all kernels that would not pop. (b) Check the normality assumption. (c) Try the Very Quick Rule. Does it work well here? Why, or why not? (d) Why might this sample not be typical?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
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(a) Construct a 90% confidence intervel for the proportion of all kernels that would not pop.
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sample proportion: 86/773 = 0.111
E = 1.645*sqrt[0.111*0.999/773) = 0.0186
90%CI: 0.111-0.0186 < p < 0.111+0.0186
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(b) Check the normality assumption.
I'll leave that to you.
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(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
(d) Why might this sample not be typical?
I am not familiar with the "Quick Rule".
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Cheers,
Stan H.
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