SOLUTION: I didn't know what category to put this under. Find Q1, Q2, and Q3 for the data set below. 5.4 2.0 6.8 3.1 2.9 4.7 2.1 5.0 1.9 3.4

Algebra ->  Probability-and-statistics -> SOLUTION: I didn't know what category to put this under. Find Q1, Q2, and Q3 for the data set below. 5.4 2.0 6.8 3.1 2.9 4.7 2.1 5.0 1.9 3.4       Log On


   



Question 157888: I didn't know what category to put this under.
Find Q1, Q2, and Q3 for the data set below.
5.4 2.0 6.8 3.1 2.9 4.7 2.1 5.0 1.9 3.4

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
 
Arrange the numbers smallest to largest:

#1  = 1.9
#2  = 2.0
#3  = 2.1
#4  = 2.9
#5  = 3.1
#6  = 3.4
#7  = 4.7
#8  = 5.0
#9  = 5.4
#10 = 6.8

There are 10 numbers in the list

To find Q%5B1%5D, which is called "the 25th percentile",
or "the 1st quartile"

Multiply 0.25 by 10, getting 2.5

Since that is not a whole number, we round up to 3.

So data value #3 is Q%5B1%5D.

So first_quartile=Q%5B1%5D=2.1,

------------------

To find Q%5B2%5D, which is called "the median", "the
50th percentile", or "the 2nd quartile"

 Multiply 0.50 by 10, getting 5

Since that is a whole number, we find the ordinary
average of data values #5 and #6:

So Q%5B2%5D=+second_quartile=median=%283.1%2B3.4%29%2F2=6.5%2F2=3.25,

------------------

To find Q%5B3%5D, which is called "the
75th percentile", or "the 3rd quartile"

Multiply 0.75 by 10, getting 7.5

Since that is not a whole number, we round up to 8.

So data value #8 is Q%5B3%5D.

So third_quartile=Q%5B3%5D=5.0

Edwin