SOLUTION: How many odd numbers of four different digits can be formed by choosing from the digits 1, 2, 3, 4, and 5?
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Question 136456: How many odd numbers of four different digits can be formed by choosing from the digits 1, 2, 3, 4, and 5? Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! In order for the number to be odd, the 'ones digit' must be odd. The other digits can be anything.
The number will be of the form ABCD - where D must be odd.
How many choices do we have for the digit 'A'? We can use any of the 5 given digits.
How many for B? Again 5 digits
How many for C? Again 5 digits?
How many for D? Only 3 (1,3 and 5).
Do the number of combinations will be
5*5*5*3 = 375
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